how to this regex in similar and faster way ?

You're calling re.search() twice, once to check if there's a match, and again to get .group(1). Instead, store the match in a variable:

match = re.search(r'data check\s*:\s*false\((\d+)\)', content)
result = match.group(1) if match else "NA"

If you're running the same regex many times (in a loop or on multiple lines), compile it once:

pattern = re.compile(r'data check\s*:\s*false\((\d+)\)')
match = pattern.search(content)
result = match.group(1) if match else "NA"

If you're matching multiple regexes on the same input and each has a similar pattern :

patterns = {
    "data_check_false": re.compile(r'data check\s*:\s*false\((\d+)\)'),
    "another_check": re.compile(r'another pattern\s*:\s*(\d+)'),
}

results = {}
for name, pattern in patterns.items():
    match = pattern.search(content)
    results[name] = match.group(1) if match else "NA"

match = re.search(r'data check\s*:\s*false\((\d+)\)', content)

result = match.group(1) if match else "NA"

• re.search(...) looks for the pattern data check : false(<number>) in the content string.
• If a match is found, group(1) extracts the number inside the parentheses.
• If no match is found, it returns "NA".